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SURDS (RADICALS) Surds are roots of arithmetic numbers that cannot be determined exactly e.g are surds. While are not surds since
RULES OF SURDS If a, b, c, d are integers then
Example Simplify the following, leaving your answers in surd form Solution
BASIC FORM OF SURD When a rational number under square root contain a factor which is a square of a number, the surd can be reduced to a simple form or its basic form. Example Reduce the following to its basic form 1 Solution 1. 2. 3. The transformation which reduced a surd to its form. can also be reversed to form a single surd Example Write the following basic form in their single surd form
Solution So then we can say that s are similar, so also
Example Simplify the following
Solution
CONJUGATE SURDS Two surds are said to be conjugate of each other, if their product gives a difference of their square. That is
Example Solution Example Simplify each of the following products Solution
RATIONALISING DENOMINATORS (i) To rationalize the denominator of the fraction
ii. To rationalize the denominator of the fraction
(iii) To rationalize the denominator of the fraction
Example By rationalizing the denominator, simplify each of the following
Example Express as equivalent fraction with rational denominator Solution
Example If x = 5 − , find the value of x2 + Solution
Example If x = Find the value of 3x2 – 5xy + 3y2
Solution
Example Simplify
Solution
Example Simplify Solution
= [Difference of two squares] = = = =
Example Simplify = = = −1
SQUARE ROOT OF SURD Given a surd x + then the square root of the given surd is Let
x Comparing the equation x = a + b …………{i}
y = 4ab ………….{ii} Solving equation {i}and{ii}simultaneously will yield the value of a and b Example Find the square root of the following 1. 12+ 2 2. 31−4 Solution 1. 12 + 2 Let the square root of 12+2 be
12 +2 12 + From equality of surds a + b = 12………{i} 2 ab = 35……..{ii} From{i} a = 12 − b Substitute a = 12 −b into {11} b = 35 12b – b2 = 35 b2 −12b −35 =0 b =7 or b = 5 Substituting the values of b a = 12−7 =or a =12−5 =7 Hence the Square root is twice
(ii) 31 −4 Let the square root 31−4
Square both sides 31− 4 31 − 4 From the equality of surd a + b = 31………..(i) −2 ab = 84………(ii) From (i) a = 31−b Substituting a = 31– b into (11) b = 84 b2 – 31b + 84 =0 = 0 b= 28 or b = 3 Substituting the values of b a = 31−28 =3 or a = 31 -3 = 28 Hence the square root of
EQUATION INVOLVING SURDS Example Solve for x in Solution
Squaring both sides 6x – 3 = 49 6x = 52 x =
EXAMPLE Solve for x in With these types of surds, it is easier to transpose one to the opposite side Squaring both sides Squaring both sides 64(3x-5) = 1+10x + 25x2 192x – 320 = 1+10x+25x2 25x2 – 182x + 321 = 0 (25x – 107) (x−3) = 0 x = 3 or x =
By substituting these two x-values in the original equation we find that x= is not a solution. Thus, the given equation has 3 as its solution
Example Solve for x in the equation
Solution Squaring both sides Squaring both sides 9x2 + 54x + 81 = 12x2 + 40x + 32 3x2 – 14x – 49 = 0 (3x+7) (x-7) = 0 x = 7 or x = By substituting these two x-values in the original equation, we see that x = does not satisfy the given equation. Thus, the equation has one solution x = 7 |
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