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DIFFERENTIATION

The process of finding the differential coefficient of a function f (x) with respect to the independent variable x is called differentiation.

The differential coefficient of a function is also called derived function or derivative of the function.

Let y = f (x) be a continuous function of x then , if it exist is called the derivative of f (x) or differential coefficient with respect to x

The notation which are commonly used for derivative of a function are

It is important to know that is either the gradient function of the curve y = f (x)  or the rate of change of y with respect to x.

 

DIFFERNTIATION FROM THE FIRST PRINCIPLE

Step to follow when differentiating from the first principle

1.         Put the function to be differentiated equal to y i.e. Let

2.         Let be an increment in the value of x and , the corresponding increment in the

value of y as a result of an increment in x so that

3.         Subtract (1) from (2) so as to obtain

4.         Divide both sides by , so as to obtain i.e

5.         Take the limits of  both sides as  

This technique of finding differential coefficient by taken into consideration of its limiting value is called differentiation from the first principle

 

EXAMPLE 1

Differentiate the following function with respect to x using first principle.

SOLUTION

EXAMPLE 2

Differentiate with respect to x fro the first principle

SOLUTION

 

DERIVATION OF xn

Hence             .

The relation is true for integral and fractional values of n            

 

EXAMPLE 3

Find the derivative if each of the following

(a)   (b) (c)   (d)

SOLUTION

 

DERIVATIVE OF

 

EXAMPLE 4

Find the derivative of the following

 

SOLUTION

GENERAL THEOREM OF DIFFERENTIATION

Theorem 1: The derivative of a constant is zero that is , where c is a constant.

Let y = c

From the first principle

Hence the derivative of a constant is zero

 

THEOREM 2: The additive constant disappear in differentiation

EXAMPLE 5 Find the derivative of the following

 

 

 

SOLUTION

 

THEOREM 3: The derivative of the product of a constant and a function is equal to the product of constant and the derivative of the function i.e.

EXAMPLE 6

Determine the differential coefficient of the following

SOLUTION

THEOREM 4:  The derivative of a sum of two functions y = u + v, where u and v are function of x and are differentiable is equal to the sum of the derivative of these functions i.e. 

EXAMPLE 7

Find the derivative of the following

THEOREM 5: given a composite function also called function of a function, in which y is a function of u and that u itself is also a function x. that is y = f (u), and u = g(x) then y =f [g (x)}

The differential coefficient of y with respect to x is equal to the derivative of the first function with respect to u times the derivative of the second function with respect to .

This is called chain rule of differentiation

 

EXAMPLE 8

Find the derivative of each of the following

SOLUTION

 

THEOREM 6: The Derivative of Product

 The derivative of a product y = uv, where u and v are function of x and are both differentiable functions, is equal to the product to the first function multiplied by the derivative of the second plus the second function multiplied by the derivative of the first i.e.

Proof  Let y = uv

Using Differentiation from first Principle

EXAMPLE 9 Find the derivative of the following

 THEOREM 7:The derivative of a Quotient

Let , where u and v are functions of x and v ¹ 0,then

Proof: Let , where u and v are functions of x .

 

EXAMPLE 10

Find the derivative of each of the following

 

 
IMPLICIT DIFFERENTIATION

An implicit function is a type of function in which the dependent and independent variable cannot be identified, i.e. the relation between the two variables is expressed in the form f (x, y).

For example, the equations  are functions in 

implicit form.

Implicit Differentiation consist of differentiating both sides of the given (defining) equation  with respect to x and then solving algebraically for

Here is an example to illustrate the technique

EXAMPLE 11

SOLUTION

The trick we are going to use to differentiate y as though we are differentiating x then multiply the result with  (that is derivative of y)

EXAMPLE 12

SOLUTION

 

EXAMPLE 13

 

 

 

SOLUTION


DERIVATIVE OF TRIGONOMETRIC FUNCTION

It is important to note the following

 

 

 

 

 

Let put all the trigonometric derivative in a table

y

dy/dx

sinx

cos x

cos x

- sin x

tan x

sec2 x

cosec x

-cosec x cot x

sec x

sec x tan x

cot x

- cosec2x

 

Example 14

SOLUTION

EXAMPLE 15

Using differentiation from first principle find  

SOLUTION

 EXAMPLE 16

Find the derivative of the following

SOLUTION

 

EXAMPLE 17

Find the derivative of the following

Example 18

Differentiate with respect to x

 

 

 

 

 

 

THE DERIVATIVE OF LOGARTHMIC FUNCTION

 

EXAMPLE 19

Differentiate with respect to x

SOLUTION

 

 

 

EXAMPLE 20

Differentiate the following with respect to x

In the course of differentiating some function, logarithmic differentiation can be applied to reduce the complication when obtaining the derivative of the given function.

 

EXAMPLE 21

Use logarithmic differentiation to obtain the derivative of the following

SOLUTION

THE DERIVATIVE OF EXPONENTIAL FUNCTION

EXAMPLE 22

Find the derivative of the following

SOLUTION

Whenever, we are differentiating an exponential function of the form . The short method to obtain the derivative is given below

                                   

EXAMPLE 23

Obtain the derivative of the following

 

HIGHER DERIVATIVE

The entire derivative obtained so far are first order derivative. That is, given  is the first order derivative

The derivative of  with respect to x is  is the called second order derivative or second differential coefficient  which is written as  pronounced dee – two – y dee x – square . The third derivative of y with respect to x is , which is denoted by .

The nth – derivative of  y with respect to x is  , which is denoted as . The nth derivative is obtained by calculating successive derivative in turn. For example to obtain ,  will first be obtained, then  will be obtained from  and lastly  will be obtained from the differentiation of

EXAMPLE 24

SOLUTION

EXAMPLE 25

SOLUTION

 

 


DIFFERENTIATION OF INVERSE TRIG FUNCTION

In this section we shall discuss the discus the derivative of inverse trig. Functions

 

Find the derivative of  

Solution

 

 

 

Worked Examples

Solution

 

Example

Solution

 


PARAMETRIC DIFFERENTIATION

Given that x and y are separately expressed as a function of a single variable say t (called parameter), then x = g (t),  y = h (t) are called parametric equation

 

Step to differentiating parametric equation

1.                   Obtain  and  separately

2.                   Use

To obtain the second order derivative

a.       Find

b.       Use

EXAMPLE 26

Find the  in terms of the parameter  when

SOLUTION

 EXAMPLE 27

 

 

 

 

 

 

 

 

 

 

 

SOLUTION

 Question1

QUESTION 2

QUESTION 3

 

QUESTION 4

QUESTION 5

QUESTION 6

QUESTION 7

QUESTION 8

QUESTION 9

 QUESTION 10

 

 Steps When Using The Derivative To Determine The Interval Of Increase And Decrease For A Function f.

1.                  Determine f1(x) from f(x)

2.                  Find all the value of x for which f1(x) = 0

3.                  Choose a test number c from each interval a < x < b, determined in step 2 and evaluate f1 (g) then

If f(g) > 0, the function f(x) is increasing on the interval a < x < b

If f(g) < 0, the function f(x) is decreasing on the interval a < x < b

 

EXAMPLE 42

Find  the interval of increase and decrease for the given function

1)      f(x) = x2 – 4x + 5

2)      f(x) = 1/3x3 – 9x + 2

SOLUTION

Interval

Test Number

f1 (x)

Conclusion

x < - 3

- 5

f1 (- 5)

f is increasing

- 3 < x < 3

1

f1 (1)

f  is decreasing

x > 3

4

f1 (4)

f  is increasing

 

 

 

 

 

MAXIMUM AND MINIMIUM VALUES RLATIVE EXTREMA

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Consider the figure above with slope of the tangent marked A, B,C, D, E, F, G, H. At point C, E, H, “peaks” occurs while at point B, D, G valley occurs. There is a horizontal tangent at F that is neither a peak nor a valley.

A peak on the graph of a function f can be otherwise called relative maximum, which a valley is called relative minimum. Relative extrema is the collective term of relative maxima and minima.

The function f(x) is said to have its maximum for x = a, if the function ceases to increase and begin to decrease at x = a

The function f(x) is said to have attained its minimum value for x = b. In the figure above C, E, H  are maximum point and B, D and G are minimum points.  The maximum and minimum points are called turning or stationary points

The following point should be noted should

  1. A relative maximum is a point on the graph of f that is least as high as any nearby point on the graph, while relative minimum is at least as low any nearby point.
  2. A function may have several maximum and minimum values
  3. Maximum and Minimum values occurs alternatively

 

CONDITION FOR MAXIMA AND MINIMA

At maximum point, the function y = f(x) changes  from an increasing to decreasing state. That is  changes from positive to negative value.  must pass through the value 0. Hence  = 0 at a maximum. Similarly, at minimum point y = f(x) changes from a decreasing to increasing state.  changes from negative to positive. In changing from negative to positive value  must pass through the value zero. Hence  = 0 at a minimum point. Thus,  = 0 for minimum and maximum point on the y = f(x).

            Though  = 0, may not necessarily be a sufficient condition for maximum or minimum point. It may happen that even if  = 0, the function may go increasing or decreasing and it may not change from increasing to decreasing state or vice versa. Such a situation is described as a point of inflection. At all point where  = 0 are called turning point or stationary points

 

CONDITION FOR MAXIMUM AND MINIMUM POINTS

 

Point of Inflection

Given that y = f(x), the function f(x) is said to a point of inflection for x = a if  and change sign

 

 

 

 

 

 

 

 

 

 

 

 


A point of inflection may not necessarily be zero unless the tangent at the point of in figure (a) and figure (b)

Hence for the point of inflection the necessary condition are as follow

 

 

 

 

EXAMPLE 43

Find the turning points on the curve , distinguish between them. Also find the maximum and minimum value of the function

 

SOLUTION

 

SECOND METHOD

 

 

EXAMPLE 44

Find the points of inflection of the function y = 3x5 – 10x3

SOLUTION

 

 

EXAMPLE 45

The curve is defined , find the stationary points are maximum point and minimum point or the point of inflection

SOLUTION

 

 

 

 

 

 

 

 Example on Minima and Maxima

EXAMPLE 46

Find two positive numbers whose sum is 50 and whose product is a large as possible

SOLUTION

 

EXAMPLE 47

Find two positive x and y whose sum is 30 and are such that xy2 is as large possible

SOLUTION

Example 48

12 is divided into two parts such that the product of the square of one part and fourth power of the other will give a maximum. Find the two numbers and their product

SOLUTION

 

Example

A piece of wire 10 feet long is divided into two portions, one being bend to form a square and the other bent to form a circle. Show that the sum of areas of the square and circle is least when the side of the square is equal to the diameter of the circle

SOLUTION

Let x be circumference of the circle and y be the perimeter of the square

 

 

 

 

 

 

Then l =10 feet

 

 

APPLICATION OF DIFFERENTIATION

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 

 


The linear (or tangent line ) approximation of f(x) at x = x0 is the function

            

The y – coordinate y1 of the point m, the tangent line corresponding to x = x1 is simply found by substituting x = x1 into equation

we define increment dx and dy by dx =x1xand dy = f(x1) – f(xo)

Using this notation, equation (3) gives the approximation

                     

To obtain dy, subtract  f (xo) from both sides to yield

            ,

where . When using this notation, we define dx , the differential of x by dx = dx so that dy = f1(x)dx

                                                                                                                         

 

Example

Use a linear approximation to approximate

 

Solution

a). We are approximating values of the function

The closest number to 8.05 whose cube root we can easily determine is 8

b)        

            The closest number to 25.4 is 27 whose cube root we know exactly as 3

           

Example

The radius of a circle increasing from 4cm to 4.03. Find the approximate increase in its area. Find the actual increase

 

Solution

Example

If the radius of a sphere decreasing by 0.5%. Find the percentage decrease in the

i)                    Surface Area    ii)   Volume

 

Solution

 

 

TANGENT AND NORMAL

 

 

 

 

 

 

 

 

 

 

 

 

 

 

Given the curve y= f(x), the line which touches the curve y = f(x) at point to be tangent at P is defined to the tangent at P. The gradient of tangent = dy/dx

The equation of the line at (x1,y1) is obtained by using                                                    y – y1 = m(xx1) as

The normal point (x1,y1) on the curve is the line perpendicular to the tangent at that point, so its gradient is  and its equation gives

Example

Find the gradient and equation of the tangent and normal to  at point (1, 5)

 

Solution

 

Example

Find the equation the tangent to the curve , which is perpendicular to the point to the tangent at point (1, 1) to the curve

 

Solution

 

Example

Find the equation of the tangent to the curve  which is parallel to the x – axis

 

Solution

 

RATE OF CHANGE

One of the numerous application of derivation is measuring the rate of change of function with respect to the variable

 

Example

A spherical ball  is inflated by pumping air into it the rate of 100cm3/min. Find the rate at which the radius is increasing when the radius is 5cm

Solution

 

 

Example

Water is running out of a conical funnel at the rate of 1cm3./sec, The radius of the base if the funnel is 5cm and its is height is10cm . Find the rate at which the water level is falling when it is falling is 4cm from the top.

SOLUTION

 

 

 


                                                                      

h                                                             

                                                                 

 

 

 

 

 

 

 

Using similar triangles

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